![]() | Everything understandable until quicksort |
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12 Dec 2011, 20:49
Marco (3 posts) |
Hi, i’ve read the book for a whole night, typing the example codes, trying hard to follow and understand what i’m doing. It’s very hard to follow for me, because of the whole recursiveness. Maybe programming for years in “c-syntax-languages” makes learning erlang so hard for me (or is it not just me who thinks it’s really not easy getting used to erlang?). So far, so good. After thinking about the examples for a while i understood them. But then came quicksort. From nothing there’s now list comprehension with comata in the generator. What does that mean? How do i read sort([X || X < – T, X < Pivot])? I hope someone could help me with understanding this, because i feel really stupid at the moment. I want to understand erlang because of the cool things you can do with it, but i’m kind of frustrated in such an early part of learning the language. |
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05 Jan 2012, 20:29
Stuart Coyle (1 post) |
The code sort([X || X < – T, X < Pivot]) can be read as: sort X for all X where X is an element of T and X is less than Pivot. List comprehensions are expressive and terse. It would be An infix operator is one which sits between it’s arguments like the + in A + B. The + operator concatenates lists. A + B is the same as calling list:append(A,B). |
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06 Jan 2012, 19:29
Marco (3 posts) |
Thank you so much. Now that you said it it’s kind of obvious to me how the list comprehension has to be read. I think my background with C style languages sometimes stands in my way of getting concepts of different syntax style languages. Can’t see the forest because of all the trees ;) |
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24 Jun 2012, 02:02
Shailen Karur (3 posts) |
One simple way of thinking about list comprehensions is to think of them as you would when you work with sets, using statements like
{X | X^2 + 2*X – 1 < 23} No doubt, this is a simple example, but it could be a useful way to build up from. HTH, |
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