15 Jul 2013, 03:42 Dave Thomas (338 posts) If you assume the variable `a` initially contains the value `2`, which of the following will match? `[ a, b, a ] = [ 1, 2, 3 ]` `[ a, b, a ] = [ 1, 1, 2 ]` `a = 1` `^a = 2` `^a = 1` `^a = 2 - a` A Possible Solution ```a = 2 #=> a → 2 [ a, b, a ] = [ 1, 2, 3 ] # ** (MatchError) no match of right hand side value: [1, 2, 3] # :erl_eval.expr/3 [ a, b, a ] = [ 1, 1, 2 ] # ** (MatchError) no match of right hand side value: [1, 1, 2] # :erl_eval.expr/3 a = 1 #=> a → 1 ^a = 2 # ** (MatchError) no match of right hand side value: 2 # :erl_eval.expr/3 ^a = 1 #=> matches. a still 1 ^a = 2 - a #=> matches. a still 1 ``` 27 Aug 2013, 04:28 Aleksey Gureiev (8 posts) From the task, it’s not clear that those matches should be performed sequentially. In other words, when I got to `^a = 2` I assumed we still have `2` in `a`, and so it would be a match. 16 Sep 2013, 02:57 Ryan Cromwell, Sr (4 posts) I too thought each line was independent. As if a multiple choice question. 09 Dec 2013, 05:55 John Marcus (1 post) Another vote for clarifying that each line was a separate question, as I assumed the variable ‘2’ was assigned for each line. 12 Dec 2013, 13:16 antonio lorusso (1 post) I got it as each line is separate statement too. 05 Jan 2014, 17:17 Federico Tomassetti (5 posts) Me too, I was expecting therefore ^a=2 to match You must be logged in to comment